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Match the statement in Column-I with statements in Column-II.
\begin{tabular}{|l|l|l|l|}
\hline \multicolumn{2}{|c|}{ Column-I } & \multicolumn{2}{c|}{ Column-II } \\
\hline A. & \( \begin{array}{l}\cos ^{-1} \lambda+\cos ^{-1} \mu+\cos ^{-1} v=3 \pi \\
\text { then } \lambda \mu+\mu v+v \lambda \text { is }\end{array} \) & p. & \( 2 n \) \\
\hline B. & \( \begin{array}{l}\text { If } \sin ^{-1} x+\tan ^{-1} x=\frac{\pi}{2} \text {, then } 2 \\
\sqrt{5}\left(2 x^{2}+1\right) \text { is }\end{array} \) & q. & \( \sin ^{-1} x-\frac{\pi}{6} \) \\
\hline C. & \( \sum_{i=1}^{2 n} \sin ^{-1} x_{i}=n \pi \) then \( \sum_{i=1}^{2 n} x_{i} \) is & r. & 10 \\
\hline D. & \( \begin{array}{l}f(x)= \\
\sin ^{-1}\left\{\frac{\sqrt{3}}{2} x-\frac{1}{2} \sqrt{1-x^{2}}\right\} ;\end{array} \) & s. & 3 \\
\( x \leq 1 \) is \( -\frac{1}{2} \leq x \leq 1 \)
\end{tabular}
(a) (A) \( \rightarrow \mathrm{s} \); (B) \( \rightarrow \mathrm{r} \); (C) \( \rightarrow \mathrm{p} \); (D) \( \rightarrow \mathrm{q} \)
(b) (A) \( \rightarrow \mathrm{r} \); (B) \( \rightarrow \) s ; (C) \( \rightarrow \mathrm{p} \); (D) \( \rightarrow \mathrm{q} \)
(c) (A) \( \rightarrow \) s ; (B) \( \rightarrow \) r ; (C) \( \rightarrow \) q ; (D) \( \rightarrow \mathrm{p} \)
(d) (A) \( \rightarrow \mathrm{p} \); (B) \( \rightarrow \mathrm{r} \); (C) \( \rightarrow \mathrm{p} \); (D) \( \rightarrow \mathrm{s} \)
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