One end of a diameter of the circle \( x^{2}+y^{2}-3 x+5 y-4=0 \) is \( (2,1) \). Find the coord...
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One end of a diameter of the circle \( x^{2}+y^{2}-3 x+5 y-4=0 \) is \( (2,1) \). Find the coordinates of the other end.
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