Parsing A Boolean Expression | Cleanest Explanation | Dry Run | Leetcode 1106 | codestorywithMIK

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This is the 25th Video of our Playlist "Stack : Popular Interview Problems" by codestorywithMIK

In this video we will try to solve an standard stack based Problem : Parsing A Boolean Expression | Cleanest Explanation | Dry Run | Leetcode 1106 | codestorywithMIK

I will explain the intuition so easily that you will never forget and start seeing this as cakewalk EASYYY.
We will do live coding after explanation and see if we are able to pass all the test cases.
Also, please note that my Github solution link below contains both C++ as well as JAVA code.

Problem Name : Parsing A Boolean Expression | Cleanest Explanation | Dry Run | Leetcode 1106 | codestorywithMIK
Company Tags : will update
My solutions on Github(C++ & JAVA) - https://github.com/MAZHARMIK/Interview_DS_Algo/blob/master/Stack/Parsing A Boolean Expression.cpp
Leetcode Link : https://leetcode.com/problems/parsing-a-boolean-expression/description/


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Summary :
The approach evaluates the boolean expression using stack-based parsing. The key parts of the solution are as follows:

solveOp() Function: This function takes a boolean operator ('!', '&', or '|') and a list of boolean values (represented as characters 't' for true and 'f' for false). It evaluates the expression based on the operator:

'!' (NOT): Negates the single value.
'&' (AND): Returns 't' if all values are true; otherwise, returns 'f'.
'|' (OR): Returns 't' if any value is true; otherwise, returns 'f'.
parseBoolExpr() Function: This function parses the boolean expression given as a string. It uses a stack to handle nested expressions:

It ignores commas ',' in the expression and processes characters.
When encountering a closing parenthesis ')', it pops values from the stack until it finds the opening parenthesis '('. These values are passed to solveOp() along with the operator just before '('.
The result of solveOp() is then pushed back onto the stack.
Final Evaluation: Once the entire string is parsed, the final result ('t' for true or 'f' for false) is at the top of the stack, which is returned as a boolean.


✨ Timelines✨
00:00 - Introduction

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