Flip Equivalent Binary Trees | Simple Recursion | Dry Run | Leetcode 951 | codestorywithMIK
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This is the 51st Video of our Playlist "Binary Tree : Popular Interview Problems" by codestorywithMIK
In this video we will try to solve a good Binary Tree Problem : Flip Equivalent Binary Trees | Simple Recursion | Dry Run | Leetcode 951 | codestorywithMIK
I will explain the intuition so easily that you will never forget and start seeing this as cakewalk EASYYY.
We will do live coding after explanation and see if we are able to pass all the test cases.
Also, please note that my Github solution link below contains both C++ as well as JAVA code.
Problem Name : Flip Equivalent Binary Trees | Simple Recursion | Dry Run | Leetcode 951 | codestorywithMIK
Company Tags : Microsoft
My solutions on Github(C++ & JAVA) - https://github.com/MAZHARMIK/Interview_DS_Algo/blob/master/Tree/Flip Equivalent Binary Trees.cpp
Leetcode Link : https://leetcode.com/problems/flip-equivalent-binary-trees/description/
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Summary :
The approach for checking if two binary trees are flip equivalent involves a recursive comparison of the trees' structures and values:
Base Case: If both nodes are null, the trees are trivially flip equivalent.
Null Handling: If one node is null and the other isn't, the trees cannot be flip equivalent.
Value Comparison: If the current nodes of both trees have the same value, two scenarios are recursively checked:
The left and right subtrees of both trees match without flipping.
The left subtree of one tree matches the right subtree of the other, and vice versa (this accounts for flipping).
Return False: If the values don't match or neither of the recursive cases holds, the trees are not flip equivalent.
This recursive approach ensures both normal and flipped subtrees are checked at each node.
✨ Timelines✨
00:00 - Introduction
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