Maximum Swap | 2 Simple Approaches | Leetcode 670 | codestorywithMIK
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This is the 46th Video of our Playlist "Strings : Popular Interview Problems" by codestorywithMIK
In this video we will try to solve a good String based Problem : Maximum Swap | 2 Simple Approaches | Leetcode 670 | codestorywithMIK
I will explain the intuition so easily that you will never forget and start seeing this as cakewalk EASYYY.
We will do live coding after explanation and see if we are able to pass all the test cases.
Also, please note that my Github solution link below contains both C++ as well as JAVA code.
Problem Name : Maximum Swap | 2 Simple Approaches | Leetcode 670 | codestorywithMIK
Company Tags : META
My solutions on Github(C++ & JAVA) - https://github.com/MAZHARMIK/Interview_DS_Algo/blob/master/strings/Maximum Swap.cpp
Leetcode Link : https://leetcode.com/problems/maximum-swap
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Summary :
1. First Approach: Swap with the Largest Digit on the Right
Objective: For each digit, find the largest possible digit to its right and swap them if it increases the number.
Steps:
Convert the number into a string to manipulate digits.
Create an array that stores the last occurrence of each digit (0-9).
For each digit, check if a larger digit exists to its right by scanning from 9 downwards. If found, swap and return the new number.
If no swap improves the number, return the original number.
2. Second Approach: Maximum Element to the Right
Objective: For each digit, find the index of the maximum element to its right, and if it’s larger than the current digit, swap them to maximize the number.
Steps:
Convert the number into a string and create an array (maxRight) to store the index of the largest digit to the right of each position.
Traverse from the rightmost digit to fill the maxRight array.
Iterate over the digits and check if a larger digit exists on the right by comparing with the values in maxRight. If found, swap and return the modified number.
If no such swap is found, return the original number.
✨ Timelines✨
00:00 - Introduction
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