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Six dice are thrown simultaneously. The
\( \mathrm{P} \) probability that exactly three of them show the

W same face and remaining three show different faces, is
(1) \( \frac{(5 !)^{2}}{6^{5}} \)
(2) \( \frac{5 !}{2 ! 6^{6}} \)
(3) \( \frac{(5 !)^{2}}{2\left(6^{6}\right)} \)
(4) \( \frac{5 !}{2\left(6^{6}\right)} \)
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