String Compression III | Simple Simulation | Leetcode 3163 | codestorywithMIK
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This is the 48th Video of our Playlist "Binary Tree : Popular Interview Problems" by codestorywithMIK
In this video we will try to solve an easy string Problem : String Compression III | Simple Simulation | Leetcode 3163 | codestorywithMIK
I will explain the intuition so easily that you will never forget and start seeing this as cakewalk EASYYY.
We will do live coding after explanation and see if we are able to pass all the test cases.
Also, please note that my Github solution link below contains both C++ as well as JAVA code.
Problem Name : String Compression III | Simple Simulation | Leetcode 3163 | codestorywithMIK
Company Tags : will update later
My solutions on Github(C++ & JAVA) - https://github.com/MAZHARMIK/Interview_DS_Algo/blob/master/strings/String Compression III.cpp
Leetcode Link : https://leetcode.com/problems/string-compression-iii
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Summary :
Initialization: Start with an empty StringBuilder to construct the compressed string and use an index i to traverse the input string.
Traverse the String: Iterate through the string character by character.
Count the number of consecutive occurrences of the current character (up to a maximum of 9).
Update the Result: Append the count followed by the character to the StringBuilder.
Move Forward: Increment i to move to the next group of characters and repeat until the end of the string.
Return: Convert the StringBuilder to a String and return the compressed result.
✨ Timelines✨
00:00 - Introduction
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