Most Beautiful Item for Each Query | Simple Explanation | Leetcode 2070 | codestorywithMIK
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This is the 32nd Video of our Playlist "BInary Search : Popular Interview Problems" by codestorywithMIK
In this video we will try to solve a medium-easy Array Binary Search Problem : Most Beautiful Item for Each Query | Simple Explanation | Leetcode 2070 | codestorywithMIK
I will explain the intuition so easily that you will never forget and start seeing this as cakewalk EASYYY.
We will do live coding after explanation and see if we are able to pass all the test cases.
Also, please note that my Github solution link below contains both C++ as well as JAVA code.
Problem Name : Most Beautiful Item for Each Query | Simple Explanation | Leetcode 2070 | codestorywithMIK
Company Tags : will update
My solutions on Github(C++ & JAVA) - https://github.com/MAZHARMIK/Interview_DS_Algo/blob/master/Arrays/Binary Search/Most Beautiful Item for Each Query.cpp
Leetcode Link : ttps://leetcode.com/problems/most-beautiful-item-for-each-query
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Summary :
This approach finds the maximum beauty value available for each price query by leveraging sorting and binary search:
Sorting by Price: First, we sort the items by price in ascending order. This allows us to use binary search efficiently later.
Non-Decreasing Beauty Update: We update the beauty values such that each item's beauty value reflects the maximum beauty seen up to that price. This ensures that if a query falls within a price range, it will return the highest possible beauty for that price or lower.
Binary Search for Each Query: For each query price, we perform a binary search to find the maximum beauty that can be obtained without exceeding the query price. If the price in the middle of our search is within the query price, we update maxBeauty and continue to search for potentially higher values on the right. If it exceeds the query price, we move left to lower prices.
✨ Timelines✨
00:00 - Introduction
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