The imaginary angular velocity of the earth for which the effective acceleration due to gravity ...

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The imaginary angular velocity of the earth for which the effective acceleration due to gravity at the equator shall be zero is equal to
(1) \( 1.25 \times 10^{-3} \mathrm{rad} / \mathrm{s} \)
(2) \( 2.50 \times 10^{-3} \mathrm{rad} / \mathrm{s} \)
(3) \( 3.75 \times 10^{-3} \mathrm{rad} / \mathrm{s} \)
(4) \( 5 . \mathrm{O} \times 1 \mathrm{O}^{-3} \mathrm{rad} / \mathrm{s} \)
[Take \( \mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2} \) for the acceleration due to gravity if the earth were at rest and radius of earth equal to \( 6400 \mathrm{~km} \).
\( \mathrm{P} \)
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