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The potential energy of a particle of mass \( m \) is given by \( U(x)=\left\{\begin{array}{cc}E_{0} ; & 0 \leq x \leq 1 \\ 0 ; & x1\end{array}\right. \)
\( \mathrm{P} \)
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\( \lambda_{1} \) and \( \lambda_{2} \) are the de-Broglie wavelengths of the particle, when \( 0 \leq x \leq 1 \) and \( x1 \) respectively. If the total energy of particle is \( 2 E_{0} \), the ratio \( \frac{\lambda_{1}}{\lambda_{2}} \) will be
(1) 2
(2) 1
(3) \( \sqrt{2} \)
(4) \( \frac{1}{\sqrt{2}} \)
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