Two Refractions through a Rectangular Glass Slab | Class 10 Physics 2022-23

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Published on September 4, 2020 8:55:49 AM ● Video Link: https://www.youtube.com/watch?v=8oHuOGCAkJg

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✅ In this video,

✔️ Class: 10th
✔️ Subject: Physics
✔️ Chapter: Light: Reflection And Refraction (Chapter 10)
✔️ Topic Name: Two Refraction through a Rectangular Glass Slab - Light: Reflection And Refraction | Class 10 Physics Chapter 10 (2022-23)
✔️ Topics Covered In This Video (by Vibhuti Ma'am): This video will provide an explanation of refraction through a rectangular glass slab as it pertains to class 10 physics. It will introduce the phenomenon of light reflection and refraction, and explain how light behaves when it passes through a glass slab. Learn how to identify the critical angle and total internal reflection with the help of diagrams and examples, and understand how this concept can be applied in daily life. Get insights on the theories and equations related to refraction, and understand how to use these to solve real-life problems. By the end of the video, viewers will have an in-depth understanding of refraction through a rectangular glass slab, and the various phenomena associated with this concept.
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00:00 Introduction: Two Refractions through a Rectangular Glass Slab
00:10 Two Refractions through a Rectangular Glass Slab
18:04 Website Overview
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Points covered in this video:-

- In this figure, PQRS is a rectangular glass slab.
- A ray of light travelling in air along AO, falls on the face PQ of glass slab at O, at angle of incidence i1 = ∠NOA.
- As the ray is going from rarer medium (air) into denser medium (glass), it bends towards normal NON’ and goes along OB at angle of refraction r1 = ∠BON’.
- According to Snell’s law:
- Applying Snell’s law of refraction at B, we get

As is clear from figure, ∠r1 = ∠r2
Therefore, sin r1 = sin r2
From equation 4; sin e = sin i1
or e = i1
i.e., angle of emergence (e) at second boundary MN of glass slab is equal to angle of incidence (i1) at first boundary KL of glass slab.
Hence, CD is parallel to AB. Thus,
Light emerges from rectangular glass slab in a direction parallel to that in which it entered the glass slab.

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