\( y=f(x) \), where \( f \) satisfies the relation \( f(x+y)=2 f(x)...
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\( y=f(x) \), where \( f \) satisfies the relation \( f(x+y)=2 f(x) \) \( +x f(y)+y \sqrt{f(x)} \forall x, y \in R \) and \( f^{\prime}(0)=0 \). Then \( f(6) \) is
\( \mathrm{P} \) equal to
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