A particle is dropped from a height \( \mathrm{h} \). Another particle which is initially at a h....

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A particle is dropped from a height \( \mathrm{h} \). Another particle which is initially at a horizontal distance \( \mathrm{d} \) from the first
\( \mathrm{P} \)
is simultaneously projected with a horizontal velocity \( \mathrm{u} \) and the two particles just collide on the ground. Then
(1) \( d^{2}=\frac{u^{2} h}{2 h} \)
(2) \( d^{2}=\frac{2 u^{2} h}{g} \)
(3) \( d=h \)
(4) \( g d^{2}=u^{2} h \)


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