If a particle is projected from origin and it follows the trajectory \( y=x-\frac{1}{2} x^{2} \)....

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If a particle is projected from origin and it follows the trajectory \( y=x-\frac{1}{2} x^{2} \), then the time of flight is
\( \mathrm{P} \)
( \( g= \) acceleration due to gravity)
(1) \( \frac{1}{\sqrt{g}} \)
(2) \( \frac{2}{\sqrt{g}} \)
(3) \( \frac{3}{\sqrt{g}} \)
(4) \( \frac{4}{\sqrt{g}} \)


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