Two particles are projected horizontally in opposite directions from the same height at \( t=0 \....
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Two particles are projected horizontally in opposite directions from the same height at \( t=0 \) with velocities
\( \mathrm{P} \)
\( 12 \mathrm{~m} / \mathrm{s} \) and \( 3 \mathrm{~m} / \mathrm{s} \). Distance between the two when there velocities become mutually perpendicular is \( (g=10 \) \( \left.\mathrm{m} / \mathrm{s}^{2}\right) \)
(1) \( 15 \mathrm{~m} \)
(2) \( 12 \mathrm{~m} \)
(3) \( 10 \mathrm{~m} \)
(4) \( 9 \mathrm{~m} \)
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