A particle is projected horizontally from a tower with velocity \( V_{0} \). Wind is blowing in ...
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A particle is projected horizontally from a tower with velocity \( V_{0} \). Wind is blowing in opposite direction and is providing a constant horizontal acceleration \( a_{0} \). If particle strikes the ground vertically then height of building is
(a) \( \frac{V_{0}^{2} g}{a_{0}^{2}} \)
(b) \( \frac{V_{0}^{2} g}{2 a_{0}^{2}} \)
(c) \( \frac{2 V_{0}^{2} g}{a_{0}^{2}} \)
(d) \( \frac{V_{0}^{2}}{g} \)
\( \mathrm{P} \)
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