Count Good Triplets | Simple Approach | Slight Improvements | Leetcode 1534 | codestorywithMIK
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Hi Everyone, this is the 79th video of our Playlist "Leetcode Easy".
Now we will be solving an easy array problem - Count Good Triplets | Simple Approach | Slight Improvements | Leetcode 1534 | codestorywithMIK
We will first solve it like a simulation problem as Brute Force and then will go to the optimal approach.
Problem Name : Count Good Triplets | Simple Approach | Slight Improvements | Leetcode 1534 | codestorywithMIK
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My solutions on Github(C++ & JAVA) - https://github.com/MAZHARMIK/Interview_DS_Algo/blob/master/Arrays/Leetcode Easy/Count Good Triplets.cpp
Leetcode Link : https://leetcode.com/problems/count-good-triplets
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Video Summary :
The approach uses a brute-force method with three nested loops to iterate over all possible triplets (i, j, k) in the array such that i is less than j and j is less than k. For each triplet, it checks whether the absolute differences between the elements satisfy the given conditions: the absolute difference between arr[i] and arr[j] is less than or equal to a, between arr[j] and arr[k] is less than or equal to b, and between arr[i] and arr[k] is less than or equal to c. If all three conditions are met, the triplet is considered "good," and a counter is incremented. Finally, the total count of such good triplets is returned.
✨ Timelines✨
00:00 - Introduction
0:12 - Motivation
0:25 - Problem Explanation
2:09 - Simple straight forward approach
6:35 - Slight improvement
8:24 - Coding it up
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