Count Symmetric Integers | 2 Detailed Approaches | Leetcode 2843 | codestorywithMIK
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Hi Everyone, this is the 78th video of our Playlist "Leetcode Easy".
Now we will be solving a good and easy problem - Count Symmetric Integers | 2 Detailed Approaches | Leetcode 2843 | codestorywithMIK
We will first solve it like a simulation problem as Brute Force and then will go to the optimal approach.
Problem Name : Count Symmetric Integers | 2 Detailed Approaches | Leetcode 2843 | codestorywithMIK
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My solutions on Github(C++ & JAVA) - https://github.com/MAZHARMIK/Interview_DS_Algo/blob/master/Mathematical/Leetcode Easy/Count Symmetric Integers.cpp
Leetcode Link : https://leetcode.com/problems/count-symmetric-integers
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Video Summary :
Approach 1 (Brute Force using Strings):
This method converts each number in the given range to a string, then checks if the number has an even number of digits. If so, it splits the number into two halves and calculates the sum of digits in each half. If both halves have equal sums, the number is considered symmetric. This is straightforward and works for numbers of any even length but is less efficient due to string operations.
Approach 2 (Optimal using Arithmetic):
This method avoids string conversion by directly analyzing digits using division and modulus operations. It leverages the observation that all 2-digit numbers divisible by 11 are symmetric (e.g., 22, 33, etc.). For 4-digit numbers, it extracts individual digits and compares the sum of the first two with the sum of the last two. This is more efficient and tailored to specific digit lengths (2 and 4).
✨ Timelines✨
00:00 - Introduction
0:21 - Motivation
0:42 - Problem Explanation
2:48 - Brute Force
5:45 - Story Points
6:30 - Optimal Approach
13:01 - Coding Approach-1
15:15 - Coding Approach-2
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