Minimum Number of Operations to Make Elements in Array Distinct | 2 Approaches | Leetcode 3396 | MIK
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Hi Everyone, this is the 76th video of our Playlist "Leetcode Easy".
Now we will be solving a good and easy problem - Minimum Number of Operations to Make Elements in Array Distinct | Brute Force | Optimal | Leetcode 3396 | codestorywithMIK
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Problem Name : Minimum Number of Operations to Make Elements in Array Distinct | Brute Force | Optimal | Leetcode 3396 | codestorywithMIK
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Video Summary :
Approach 1: Brute Force
This method iterates through the array in segments of three elements, checking for duplicate values within each segment. If a segment contains duplicates, it increments an operation counter and continues to the next segment. The process repeats until a segment without duplicates is found, at which point the function returns the current count of operations.
Approach 2: Reverse Iteration
Starting from the end of the array, this approach traverses backward while maintaining a set of encountered elements. For each element, it checks if it has already been seen. If a duplicate is found, it calculates and returns the minimum number of operations required, based on the position of the duplicate. If no duplicates are encountered during the traversal, it returns zero, indicating no operations are needed.
✨ Timelines✨
00:00 - Introduction
0:19 - Motivation
0:28 - Problem Explanation
2:55 - Thought Process - Brute Force
8:23 - Thought Process - Optimal
12:42 - One More Example Dry Run
14:37 - Coding it up
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