Daily Practice Questions (Part 4) - Light: Reflection And Refraction | Class 10 Physics 2022-23
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In this video,
โ๏ธ Class: 10th
โ๏ธ Subject: Physics
โ๏ธ Chapter: Light: Reflection And Refraction (Chapter 10)
โ๏ธ Topic Name: Daily Practice Questions (Part 4) - Light: Reflection And Refraction | Class 10 Physics Chapter 10 (2022 - 2023)
โ๏ธ Topics Covered In This Video (by Vibhuti Ma'am): This YouTube video tackles the topic of light, reflection and refraction which is the 10th chapter of Class 10 Physics for the 2022 - 2023 academic year. It provides daily practice questions to help the student understand the topic better. Led by experienced tutor and mentor Vibhuti Mam, the video explains the concepts with apt examples and diagrams. It will help the student strengthen their knowledge of the topic and enjoy an engaging learning experience.
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00:00 Introduction: Light: Reflection And Refraction
00:08 Question 1 to 5: Daily Practice Questions: Light: Reflection And Refraction
1. Radius of curvature of a concave mirror is 25 cm. What is its focal length?
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Points covered in this video:-
Daily Practice Questions -
1. Radius of curvature of a concave mirror is 25 cm. What is its focal length?
a. 11.5 cm
b. 12 cm
c. 12.5 cm
d. 13 cm
Solution 1. Here R = 25 cm,
f = ?
From
f = R/2
= 25/2
= 12.5 cm
2. An erect image 3 times the size of the object is obtained with a concave mirror of radius of curvature 36 cm. What is the position of the object?
a. -12 cm
b. +12 cm
c. -28 cm
d. -10 cm
Solution 2. Here,
m = 3
R = -36 cm
u = ?
As, m = -v/u
3 = -v/u
v = -3u
As 1/v + 1/u = 1/f = 2/R, 1/-3u + 1/u = 2/-36
Or, 3u = -36
u = -12 cm
3. A concave mirror produces a real image 10 mm tall, of an object 2.5 mm tall placed at 5 cm from the mirror. Calculate focal length of the mirror and the position of the image?
a. + 8 cm and 15 cm
b. - 4 cm and -20 cm
c. + 4 cm and +20 cm
d. - 6 cm and -15 cm
Solution 3. Here,
h2 = -10 mm, h1 = 2.5 mm, u = -5 cm
As, m = h2/h1 = -v/u
= -10/2.5 = -v/-5
v = -20 cm
Negative sign of v shows that image is real.
1/f = 1/v + 1/u
= 1/-20 - 1/5 = -20/5
f = - 4 cm
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