For all \( n \in N, \sum n \) (a) \( \frac{(2 n+1)^{2}}{8} \) (b) \( \frac{(2 \mathrm{n}+1)^{2}}...

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For all \( n \in N, \sum n \)
(a) \( \frac{(2 n+1)^{2}}{8} \)
(b) \( \frac{(2 \mathrm{n}+1)^{2}}{8} \)
(c) \( =\frac{(2 n+1)^{2}}{8} \)
(d) None of these
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