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For the given diagram the correct truth table is
(1)
\begin{tabular}{cc|c}
\( \mathrm{A} \) & \( \mathrm{B} \) & \( \mathrm{E} \) \\
\hline 0 & 0 & 1 \\
0 & 1 & 0 \\
1 & 0 & 1 \\
1 & 1 & 0
\end{tabular}
(2)
\begin{tabular}{cc|c}
\( \mathrm{A} \) & \( \mathrm{B} \) & \( \mathrm{E} \) \\
\hline 0 & 0 & 1 \\
0 & 1 & 0 \\
1 & 0 & 0 \\
1 & 1 & 1
\end{tabular}
(3)
\begin{tabular}{cc|c}
\( \mathrm{A} \) & \( \mathrm{B} \) & \( \mathrm{E} \) \\
\hline 0 & 0 & 0 \\
0 & 1 & 0 \\
1 & 0 & 0 \\
1 & 1 & 0
\end{tabular}
(4)
\begin{tabular}{cc|c}
\( \mathrm{A} \) & \( \mathrm{B} \) & \( \mathrm{E} \) \\
\hline 0 & 0 & 0 \\
0 & 1 & 1 \\
1 & 0 & 1 \\
1 & 1 & 0
\end{tabular}
(4) (ㅁ) (D) (अ) (9)
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