\( \int \frac{e^{x}}{x+1}\{1+(x+1) \log (x+1)\} d x=\ldots \ldots \ldots \) (A) \( \frac{e^{x}}{...
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0\( \int \frac{e^{x}}{x+1}\{1+(x+1) \log (x+1)\} d x=\ldots \ldots \ldots \)
(A) \( \frac{e^{x}}{x+1}+c \)
(B) \( e^{x} \log (x+1)+c \)
(C) \( e^{x} \log (x+1)-(x+1) \)
(D) \( e^{x}[\log (x+1)+x]+c \)
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