Maximum Product of Two Elements in an Array | 2 Approaches | Leetcode-1464
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This is the 7th Video of our "Leetcode Easy" Playlist.
In this video we will try to solve an easy problem with 2 simple approaches - Maximum Product of Two Elements in an Array (Leetcode - 1464).
I will explain the intuition so easily that you will never forget and start seeing this as cakewalk EASYYY.
We will do live coding after explanation and see if we are able to pass all the test cases.
Also, please note that my Github solution link below contains both C++ as well as JAVA code.
Problem Name : Maximum Product of Two Elements in an Array
Company Tags : Will soon update
My solutions on Github(C++ & JAVA) : https://github.com/MAZHARMIK/Interview_DS_Algo/blob/master/Arrays/Leetcode%20Easy/Maximum%20Product%20of%20Two%20Elements%20in%20an%20Array.cpp
Leetcode Link : https://leetcode.com/problems/maximum-product-of-two-elements-in-an-array
My DP Concepts Playlist : https://youtu.be/7eLMOE1jnls
My Graph Concepts Playlist : https://youtu.be/5JGiZnr6B5w
My GitHub Repo for interview preparation : https://github.com/MAZHARMIK/Interview_DS_Algo
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//Approach-1
The approach involves iterating through the vector, updating the maximum product (result) by comparing it with the product of the current maximum element (maxNum) and the current element (nums[i]) decremented by 1. The maximum element (maxNum) is updated in each iteration to ensure that it represents the maximum value encountered so far. The final result is the maximum product calculated based on these conditions.
//Approach-2
The approach involves iterating through the vector, maintaining the two maximum values (firstMax and secondMax) encountered so far. If a new element is greater than the current maximum (firstMax), the maximum values are updated accordingly. Finally, the method returns the maximum product calculated using these two maximum values, each decremented by 1. The logic ensures the selection of the two largest elements in the vector for the product calculation.
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✨ Timelines✨
00:00 - Introduction
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