Find Minimum Time to Reach Last Room II | Using Same Code | Leetcode 3342 | codestorywithMIK

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Published on May 8, 2025 1:56:36 AM ● Video Link: https://www.youtube.com/watch?v=SVTezUTAKMk

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Find Minimum Time to Reach Last Room I -    • Find Minimum Time to Reach Last Room ...  
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Dijkstra's Algorithm | PART-2 -    • Dijkstra's Algorithm | PART-2 | (Micr...  

Hi Everyone, this is the 74th video of our Playlist "Graphs : Popular Interview Problems".
Now we will be solving a good Graph practice problem on Dijkstra's Algorithm - Find Minimum Time to Reach Last Room II | Using Same Code | Leetcode 3342 | codestorywithMIK

We will simply use the same code we had done for Leetcode 3341 - Find Minimum Time to Reach Last Room I
So don't forget to watch Leetcode 3341 video (link mentioned above)

Problem Name : Find Minimum Time to Reach Last Room II | Using Same Code | Leetcode 3342 | codestorywithMIK
Company Tags : will update later
My solutions on Github(C++ & JAVA) - https://github.com/MAZHARMIK/Interview_DS_Algo/blob/master/Graph/Dijkstra'a Based Problems/Find Minimum Time to Reach Last Room II.cpp
Leetcode Link : https://leetcode.com/problems/find-minimum-time-to-reach-last-room-ii


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Video Summary :
This approach uses Dijkstra's algorithm to find the minimum time to reach the bottom-right cell in a grid where each cell may require waiting before entry. The movement cost alternates between 1 and 2 with each step, which is determined using the Manhattan distance from the start cell (0,0). At each step, we compute the wait time, movement cost, and arrival time, updating only if we find a faster path. The priority queue ensures cells are explored in order of the shortest known arrival time.


✨ Timelines✨
00:00 - Introduction
0:23 - Motivation
0:39 - Problem Explanation
6:27 - Same as Leetcode 3341
7:33 - How to calculate alternating moveCost
16:40 - One minor change
17:24 - Coding it up

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