One vertex of a triangle of maximum area that can be
inscribed in the curve \( |z-2 i|=2 \) is \.... VIDEO
One vertex of a triangle of maximum area that can be
\( \mathrm{P} \)
inscribed in the curve \( |z-2 i|=2 \) is \( 2+2 i \). Then the remaining vertices is/are
(1) \( -1+i(2+\sqrt{3}) \)
(2) \( \quad-1-i(2+\sqrt{3}) \)
(3) \( -1+i(2-\sqrt{3}) \)
(4) \( \quad-1-i(2-\sqrt{3}) \)
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