Take K of Each Character From Left and Right | 2 Approaches | Leetcode 2516 | codestorywithMIK
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This is the 32nd Video of our Playlist "Sliding Window : Popular Interview Problems" by codestorywithMIK
In this video we will try to solve a classic but a little tricky Sliding Window Problem : Take K of Each Character From Left and Right | Brute Force | Khandani Template | Leetcode 2516 | codestorywithMIK
I will explain the intuition so easily that you will never forget and start seeing this as cakewalk EASYYY.
We will do live coding after explanation and see if we are able to pass all the test cases.
Also, please note that my Github solution link below contains both C++ as well as JAVA code.
Problem Name : Take K of Each Character From Left and Right | Brute Force | Khandani Template | Leetcode 2516 | codestorywithMIK
Company Tags : will update later
My solutions on Github(C++ & JAVA) - https://github.com/MAZHARMIK/Interview_DS_Algo/blob/master/Sliding Window/Take K of Each Character From Left and Right.cpp
Leetcode Link : https://leetcode.com/problems/take-k-of-each-character-from-left-and-right
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Summary :
Recursive Approach:
Idea: This approach uses recursion to explore all possible ways to delete characters from either the left or right of the string to ensure that at least k occurrences of 'a', 'b', and 'c' are present in the deleted characters.
Key Features:
Maintains a frequency array to track the counts of 'a', 'b', and 'c'.
Recursively tries both options: delete from the left or delete from the right.
Returns the minimum number of deletions required.
Drawbacks: The time complexity is exponential (O(2^n)), making it impractical for large inputs.
Sliding Window Approach:
Idea: This approach optimizes the problem using the sliding window technique to find the largest substring (window) that can remain untouched while ensuring the deleted characters meet the k requirement for 'a', 'b', and 'c'.
Key Features:
Uses two pointers (i and j) to define the current window and dynamically adjust it based on character counts.
If the current window causes any character count to fall below k, it shrinks the window from the left to restore validity.
Computes the minimum deletions as total length - max valid window size.
Advantages: Efficient with a time complexity of O(n), suitable for large inputs.
✨ Timelines✨
00:00 - Introduction
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