Count Unguarded Cells in the Grid | Simple Explanation | Leetcode 2257 | codestorywithMIK
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This is the 123rd Video of our Playlist "Array 1D/2D : Popular Interview Problems" by codestorywithMIK
In this video we will try to solve a simple 2D Array based problem : Count Unguarded Cells in the Grid | Simple Explanation | Leetcode 2257 | codestorywithMIK
I will explain the intuition so easily that you will never forget and start seeing this as cakewalk EASYYY.
We will do live coding after explanation and see if we are able to pass all the test cases.
Also, please note that my Github solution link below contains both C++ as well as JAVA code.
Problem Name : Count Unguarded Cells in the Grid | Simple Explanation | Leetcode 2257 | codestorywithMIK
Company Tags : will update
My solutions on Github(C++ & JAVA) - https://github.com/MAZHARMIK/Interview_DS_Algo/blob/master/Arrays/2-D Array/DFS/Count Unguarded Cells in the Grid.cpp
Leetcode Link : https://leetcode.com/problems/count-unguarded-cells-in-the-grid
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Summary :
Approach 1: Simple Simulation
Description:
For each guard, simulate its line of sight in all four directions (up, down, left, and right).
If the line of sight encounters a wall or another guard, it stops.
Mark all cells in the line of sight as guarded.
Key Steps:
Initialize the grid with guards, walls, and empty spaces.
For each guard, mark its line of sight using a loop in each direction.
Count the number of unguarded cells at the end.
Approach 2: Depth-First Search (DFS)
Description:
Perform a depth-first search (DFS) from each guard to simulate its line of sight in a specified direction.
The DFS stops when it encounters a wall, another guard, or already marked cells.
Key Steps:
Initialize the grid with guards, walls, and empty spaces.
Use DFS to recursively mark all cells in the guard’s line of sight for each direction (up, down, left, right).
Count unguarded cells in the grid after processing all guards.
✨ Timelines✨
00:00 - Introduction
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