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Column-I gives four different situation. In final statement of each situation two vector quantities are compared. The result of comparison is given in column-II. Match the statement in column-I with the correct comparison(s) in column-II:
Column-I
Column-II
\( \mathrm{P} \)
(a) Stone is projected from ground at an angle \( \theta \) with horizontal \( \left(\theta-90^{\circ}\right) \).
(p) same in magnitude
W
Neglect the effect of air friction. Then between the two instants when it is at same height (above ground), its average velocity and horizontal component of velocity are
(b) For four particles A. B, C \& D, the velocities of one with respect to other
(q) different in magnitude are given as \( \vec{V}_{D C} \) is \( 20 \mathrm{~m} / \mathrm{s} \) towards north, \( \vec{V}_{\mathrm{BC}} \) is \( 20 \mathrm{~m} / \mathrm{s} \) towards east and \( \vec{V}_{\mathrm{BA}} \) is \( 20 \mathrm{~m} / \mathrm{s} \) towards south. Then \( \overrightarrow{\mathrm{V}}_{\mathrm{BC}} \) and \( \overrightarrow{\mathrm{V}}_{\mathrm{AL}} \) are
(c) Two blocks of masses 4 and \( 8 \mathrm{~kg} \) are placed on ground as shown.
(r) same in direction Then the net force exerted by earth on block of mass \( 8 \mathrm{~kg} \) and normal reaction exerted by \( 8 \mathrm{~kg} \) block on earth are (note that earth includes ground)
(d) For a particle undergoing rectilinear motion with uniform acceleration, the
(s) opposite in direction magnitude of displacement is half the distance covered in some time interval. The magnitude of final velocity is less than magnitude of initial velocity for this time interval. Then the initial velocity and average velocity for this time interval are
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