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If sum of \( x \) terms of a series is \( S_{x}=\frac{1}{(2 x+3)(2 x+1)} \) whose \( r^{\text {th }} \) term is \( T_{r} \). Then, \( \sum_{r=1}^{n} \frac{1}{T_{r}} \) is equal to
(A) \( \frac{1}{4} \sum(2 r+1)(2 r-1)(2 r+3) \)
(B) \( -\frac{1}{4} \sum(2 r+1)(2 r-1)(2 r+3) \)
(C) \( \sum(2 r+1)(2 r-1)(2 r+3) \)
(D) none of these.
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