Match the following columns:
\begin{tabular}{|l|c|l|c|}
\hline \multicolumn{2}{|c|}{ Column-I } ....
Match the following columns:
\begin{tabular}{|l|c|l|c|}
\hline \multicolumn{2}{|c|}{ Column-I } & \multicolumn{2}{c|}{ Column-II } \\
\hline (A) & \begin{tabular}{c}
\( C_{0}+3 C_{1}+5 C_{2}+ \) \\
\( \ldots \ldots \ldots= \)
\end{tabular} & (P) & \( 2^{n}-(n+2) \) \\
\hline (B) & \begin{tabular}{r}
\( { }^{n} C_{2}+{ }^{n} C_{3}+{ }^{n} C_{4}+\ldots+ \) \\
\( { }^{n} C_{n-1}= \)
\end{tabular} & (Q) & \( \frac{1}{(n+1)(n+2)} \) \\
\hline (C) & \( \frac{C_{0}}{2}-\frac{C_{1}}{3}+\frac{C_{2}}{4}-\frac{C_{3}}{5}+\ldots= \) & (R) & \( \frac{\lfloor 2 n-1}{\lfloor n-1\lfloor n-1} \) \\
\hline (D) & \( C_{1}^{2}+2 C_{2}^{2}+3 C_{3}^{2}+\ldots+n C_{n}^{2}= \) & (S) & \( (n+1) 2^{n} \) \\
\hline
\end{tabular}
(1) \( \mathrm{A} \rightarrow \mathrm{R} ; \mathrm{B} \rightarrow \mathrm{S} ; \mathrm{C} \rightarrow \mathrm{Q} ; \mathrm{D} \rightarrow \mathrm{P} \)
(2) \( \mathrm{A} \rightarrow \mathrm{Q} ; \mathrm{B} \rightarrow \mathrm{P} ; \mathrm{C} \rightarrow \mathrm{R} ; \mathrm{D} \rightarrow \mathrm{S} \)
(3) \( \mathrm{A} \rightarrow \mathrm{R} ; \mathrm{B} \rightarrow \mathrm{P} ; \mathrm{C} \rightarrow \mathrm{Q} ; \mathrm{D} \rightarrow \mathrm{S} \)
(4) \( \mathrm{A} \rightarrow \mathrm{S} ; \mathrm{B} \rightarrow \mathrm{P} ; \mathrm{C} \rightarrow \mathrm{Q} ; \mathrm{D} \rightarrow \mathrm{R} \)
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